Why doesn't the following work in eshell
$ (echo "foo")
Symbol's function definition is void: echo
What I tried:
googled eshell parenthesis not working
More Context:
Eventually I'm trying to run (source functions.sh; myCoolFunc)
1
asked Dec 28 '17 at 13:21
0
You incorrectly assumed that eshell starts your default shell
specified in /etc/passwd but it doesn't, it's a shell on its
own:
Eshell is a shell-like command interpreter implemented in Emacs Lisp. It invokes no external processes except for those requested by the user. It is intended to be an alternative to the IELM (see Emacs Lisp Interaction) REPL for Emacs and with an interface similar to command shells such as bash, zsh, rc, or 4dos.
The source command you want to run does not work with bash files
in eshell as you would expect it but with eshell commands as help
mentions:
~ $ source -h
usage: source FILE [ARGS]
Invoke the Eshell commands in FILE in a subshell, binding ARGS to $1,
$2, etc.
-h, --help show this usage screen
In order to achieve what you want in eshell buffer you need to start
bash manually:
M-x eshell
~ $ bash
$ (echo hi)
hi
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if I''m starting bash manually like you suggested, am I better off simple using M-x shell instead? – american-ninja-warrior Dec 29 '17 at 0:18
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Probably yes if you are not interested in using
eshellat all. – Arkadiusz Drabczyk Dec 29 '17 at 7:47 -
@joshsverns: See What should I do when someone answers my question? – Arkadiusz Drabczyk Dec 30 '17 at 16:28
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