2

I have a text with a number of coherent strings, e.g.:

ax923fasd
asidna1
xxa008

Is there a quick way to convert these so that there be a space between each of them, i.e.:

a x 9 2 3 f a s d
a s i d n a 1
x x a 0 0 8
3
  • 1
    Is your text in a buffer, or is it a string object?
    – phils
    Mar 11, 2018 at 19:44
  • If this is text in a buffer, do you want to do this interactively (via command) or in Lisp code?
    – Drew
    Mar 11, 2018 at 22:42
  • text is in a buffer; would like to do it interactively; phils answer down below solved it nicely.
    – miri sueß
    Mar 12, 2018 at 19:54

1 Answer 1

4

There are lots of ways you could do that.

Assuming this is text in a buffer, a simple regexp-based approach is to use M-x replace-regexp to replace . with \& (n.b. that's \&SPC) to replace each non-newline character with itself followed by a space.

As that does match the final character of each non-blank line, that will introduce a space at the end of those lines, which you might wish to clean up with delete-trailing-whitespace or similar.

A fancier interactive regexp replacement which doesn't append the trailing space would be:

\,(concat \& (if (eolp) "" " "))

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