When running a process from a timer, this message is printed a lot.

Is there a way to suppress the message entirely?

For reference see: https://emacs.stackexchange.com/a/50681/2418

  • 3
    Well the message is there for a reason -- Emacs has been told to wait for output from a process for an unlimited duration, without allowing the user to interrupt. Instead of suppressing the message, perhaps it would make best sense to avoid it from being issued in the first place.
    – phils
    Commented Feb 18, 2020 at 10:48
  • Right, this should be worked around somehow, the issue is - I have no idea how. I wanted to run a spell checker on a timer, which seems to be possible to do wcheck package does it, however the code is fairly complex and I'd need to spend much more time digging into it to figure out how it works.
    – ideasman42
    Commented Feb 18, 2020 at 22:53

1 Answer 1


From what I can tell the answer is no.

However, this can be worked around (albeit a hack).

  • Disable logging.
  • Run the operation which causes the message.
  • Clear the message.
  • Enable logging again.
  • 1
    There is also inhibit-message (still a hack, just slightly more concise).
    – npostavs
    Commented May 26, 2019 at 14:03
  • 1
    This happens not to work in this case, I think because the message call is from C code.
    – ideasman42
    Commented May 26, 2019 at 14:09
  • 1
    Hmm, I thought the point of inhibit-message is that it should work on C code, unlike advising message which doesn't. Although looking at its docstring, I notice inhibit-message doesn't inhibit logging, just the display. So if you want to keep the log clear too, it's not really that much more concise.
    – npostavs
    Commented May 26, 2019 at 14:32
  • 1
    @npostavs (let ((inhibit-message t) (message-log-max nil)) ...) is the best way I know of to do both.
    – phils
    Commented Feb 18, 2020 at 10:40

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