Generate different uuid in every line?

Question

I need to replace guid_here by different uuid.

provider [guid_here]
[guid_here] provider
test again [guid_here]
test again2 [guid_here]
test [guid_here] again2 

I use this approach.

Install package "uuid" - UUID

I need create uuid exactly in the cursor place. To do this I create custom function:

  (defun uuid-insert()
      (interactive)
      (require 'uuid)
      (insert (upcase (uuid-string))))

and bind to key:

(global-set-key (kbd "C-c C-'") 'uuid-insert)

Also I need package multiple-cursor multiple-cursor

and here steps.

1. Select guid_here

2. Use mc/mark-all-like-this

3. Press Del

4. Use my custom function uuid-string to insert uuid in every line. I must use keybinding for this - C-c C-' . If use by function name uuid-string it's not work.

As you can see, now in every line has different uuid. Nice.

It's very cool.

Is it best approach to generate uuid in every lines?

Answer 1

The way I'd do this is with search and replace. You can call Lisp code from a regexp replacement with \,(my-function …). So call M-x replace-regexp (or C-M-% which is bound to query-replace-regexp by default). Use \[guid_here] as the regexp to search for and [\,(upcase (uuid-string))] as the replacement text.