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This statements generates a list of (list filename buf), How could this be written to include an index as well?

eg: (list index filename buf) where the index would be a counter, starting at zero, increment 1 for each item.

(mapcar
  (lambda (buf) (list (buffer-file-name buf) buf))
  (seq-filter 'buffer-file-name (buffer-list))))
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(let ((my-counter  0))
  (mapcar (lambda (buf) (list (cl-incf my-counter) (buffer-file-name buf) buf))
          (seq-filter 'buffer-file-name (buffer-list))))

Or if you want to use a global counter (e.g. for other purposes too):

(defvar my-counter 0 "My wonderful counter.")

(mapcar (lambda (buf) (list (cl-incf my-counter) (buffer-file-name buf) buf))
        (seq-filter 'buffer-file-name (buffer-list))))

If you don't want to use cl-incf then use (setq my-counter (1+ my-counter)).

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  • Updated question to clarify what the index is.
    – ideasman42
    Aug 17 '19 at 14:30
  • Can a locally defined variable be used (via let?) so it doesn't need to be global.
    – ideasman42
    Aug 17 '19 at 14:38
  • Note, I though it might be possible to use a sequence generator in this case and merge the two sequences.
    – ideasman42
    Aug 17 '19 at 14:39
  • What two sequences? But yes, lots of things are possible.
    – Drew
    Aug 17 '19 at 14:41
  • something like this: (merge-two-sequences (sequence of items) (generate-range))
    – ideasman42
    Aug 17 '19 at 14:43

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