I need to write a command which will apply to my buffer custom, predefined copy-and-replace sequence.

What I have is:

(defun custom-processor ()
  "Formats logs to human-readable format"
  ((replace-in-the-buffer "\n" "\n\n\n")
   (replace-in-the-buffer "\t" "\n")))

(defun replace-in-the-buffer (from to)
  "Replaces in the current buffer all occurences of from to to (not interactively)"
  (while (re-search-forward from nil t)
    (replace-match to nil nil)))

It is basically working for simple characters like letters or numbers, but the case is I need to use it with new lines (\n) and tabs (\t) - the error I get is:

Debugger entered--Lisp error: (invalid-function (replace-in-the-buffer "\n" "\n\n\n"))
  ((replace-in-the-buffer "\n" "\n\n\n") (replace-in-the-buffer "\011" "\n"))
  eval((custom-processor) nil)
  funcall-interactively(eval-last-sexp nil)
  call-interactively(eval-last-sexp nil nil)

I use EMACS for 10y+ but now just starting to leverage it with Lisp programming. Please help.

  • This is a duplicate question, but I don't have time now to find the duplicate. Emacs Lisp is a "Lisp 2". When evaluating (<something> ...), something must be a lambda expression or a named function. Your (replace-in-the-buffer "\n" "\n\n\n") is neither. – Drew Jun 2 '20 at 16:42
  • I'm hoping someone finds the duplicate - I saw one recently, so people can vote to close. Thx. – Drew Jun 2 '20 at 16:44

Double parenthesis are the culprit.

I guess you forgot to type progn

(defun custom-processor ()
  "Formats logs to human-readable format"
    (replace-in-the-buffer "\n" "\n\n\n")
    (replace-in-the-buffer "\t" "\n")))

or just remove them:

(defun custom-processor ()
  "Formats logs to human-readable format"
  (replace-in-the-buffer "\n" "\n\n\n")
  (replace-in-the-buffer "\t" "\n"))
  • thanks for answering - however - can you please advice with one more thing: I cannot find how to replace-in-the-buffer TAB character for sth else. The \t doesn't work. Can you help? – supertramp Aug 20 '20 at 8:55
  • Cannot reproduce that behavior evaluating the provided code. Work as intended. – Muihlinn Aug 20 '20 at 9:28

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