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How should one type numbers like 10^(-2.5) using the 1e... notation in calc using algebraic-mode ? ATM, 1e-2.5 is parsed as (1e-2)*0.5 and indeed evaluates to 5e-3 instead of 3.16e-3.

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Use algebraic entry: '1*10^-2.5. This is also necessary when using an entry radix of 15 or higher (such as hexadecimal), where e is a valid digit.

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  • I find it nevertheless confusing that the parser should split something like -2.5. – wilk Jun 17 '20 at 19:03

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