8

Let's say I have the following table:

| Name   | Age              | Date of Birth    | Income |
|--------+------------------+------------------+--------|
| Joe    |                  | <1984-02-20 Mon> |  84000 |
| Mark   |                  | <1974-04-15 Mon> | 120000 |
| Sophie |                  | <1970-08-28 Fri> | 150000 |
| Anna   |                  | <1988-02-29 Mon> | 160000 |

I want the second column to be the amount of years elapsed since the date in the third column.

I can't figure out how to do this with the TBLFM settings.

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1 Answer 1

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9

Is it something like the example below:

| Name   | Age          | Date of Birth    | Income |
|--------+--------------+------------------+--------|
| Joe    | 30 years old | <1984-02-20 Mon> |  84000 |
| Mark   | 40 years old | <1974-04-15 Mon> | 120000 |
| Sophie | 44 years old | <1970-08-28 Fri> | 150000 |
| Anna   | 26 years old | <1988-02-29 Mon> | 160000 |
#+TBLFM: $2=(now()-$3)/365;%d years old
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3
  • Thank you! Where can I find out that there are such things as now() ?
    – Trevoke
    Commented Jan 28, 2015 at 12:33
  • 1
    gnu.org/software/emacs/manual/html_mono/…
    – wdkrnls
    Commented Jan 28, 2015 at 12:54
  • 1
    @Trevoke Another way, which would typically work is to try C-h f calc-now - most Calc functions will have a corresponding Emacs Lisp function with the name prefixed with calc-.
    – wvxvw
    Commented Jan 28, 2015 at 15:37

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