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In Emacs regex, \n doesn't match a new line character \n.
$ matches the position between a new line
character and the character right before the new line character.
e.g. for a string abc\n, $ matches the position between c and
\n?\n?
$ matches the end of the line, not the newline character which comes after the end of the line.C-M-s C-q C-j. C-q is the default binding for quoted-insert and works in the minibuffer too. This expression literally searches for a newline: C-j.
(looking-at "^J") where ^J is inserted by C-q C-j), the C-q C-j approach always works. But when using elisp functions like the same looking-at \n works too; M-: (looking-at "\n") RET will eval to true if the cursor is at the end of the line (and there's a newline after that).
– Kaushal Modi
Feb 25 '15 at 0:09
regexp-builder, you're able to recognize a new line with [\n].
– Nsukami _
Feb 25 '15 at 0:29
As Dan comments, the regex that matches a newline is a newline.
You can represent a newline in a quoted string in elisp as "\n". There is no special additional regexp-specific syntax for this -- you just use a newline, exactly like any other literal character.
If you are entering a regexp interactively then you can insert the newline with C-qC-j, as kaushalmodi's answer points out.
\n doesn't match a new line character.
– Tim
Apr 9 '15 at 17:10
C-q C-j is the most reliable way to type a newline at a prompt.
– phils
Apr 9 '15 at 22:21
(re-search-forward "\n")works fine for me. – Dan♦ Feb 25 '15 at 0:37abc\r\ninstead ofabc\n. – Jordon Biondo Feb 25 '15 at 15:53\nton. my buffer is in Fundamental mode. This happens to any text, so any text with new line or letternis a working example – Tim Feb 27 '15 at 2:17\r\ntorn– Tim Feb 27 '15 at 2:18