New answers tagged characters
8
Remove the backslashes before e, 0 and 9.
(let ((char ?e))
(if (<= ?0 char ?9)
(message "It's a digit")
(message "It's not a digit")))
With the backslashes:
\e is the escape char - ASCII 27.
\0 is the null char - ASCII 0.
\9 isn't special, so it's the same as 9 - ASCII 57.
27 is >= 0 and <= 57.
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